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直線與圓的位置關(guān)系教學(xué)設(shè)計(jì)人教A版高中數(shù)學(xué)選擇性必修第一冊(cè)
切線方程的求法1.求過(guò)圓上一點(diǎn)P(x0,y0)的圓的切線方程:先求切點(diǎn)與圓心連線的斜率k,則由垂直關(guān)系,切線斜率為-1/k,由點(diǎn)斜式方程可求得切線方程.若k=0或斜率不存在,則由圖形可直接得切線方程為y=b或x=a.2.求過(guò)圓外一點(diǎn)P(x0,y0)的圓的切線時(shí),常用幾何方法求解設(shè)切線方程為y-y0=k(x-x0),即kx-y-kx0+y0=0,由圓心到直線的距離等于半徑,可求得k,進(jìn)而切線方程即可求出.但要注意,此時(shí)的切線有兩條,若求出的k值只有一個(gè)時(shí),則另一條切線的斜率一定不存在,可通過(guò)數(shù)形結(jié)合求出.例3 求直線l:3x+y-6=0被圓C:x2+y2-2y-4=0截得的弦長(zhǎng).思路分析:解法一求出直線與圓的交點(diǎn)坐標(biāo),解法二利用弦長(zhǎng)公式,解法三利用幾何法作出直角三角形,三種解法都可求得弦長(zhǎng).解法一由{■(3x+y"-" 6=0"," @x^2+y^2 "-" 2y"-" 4=0"," )┤得交點(diǎn)A(1,3),B(2,0),故弦AB的長(zhǎng)為|AB|=√("(" 2"-" 1")" ^2+"(" 0"-" 3")" ^2 )=√10.解法二由{■(3x+y"-" 6=0"," @x^2+y^2 "-" 2y"-" 4=0"," )┤消去y,得x2-3x+2=0.設(shè)兩交點(diǎn)A,B的坐標(biāo)分別為A(x1,y1),B(x2,y2),則由根與系數(shù)的關(guān)系,得x1+x2=3,x1·x2=2.∴|AB|=√("(" x_2 "-" x_1 ")" ^2+"(" y_2 "-" y_1 ")" ^2 )=√(10"[(" x_1+x_2 ")" ^2 "-" 4x_1 x_2 "]" ┴" " )=√(10×"(" 3^2 "-" 4×2")" )=√10,即弦AB的長(zhǎng)為√10.解法三圓C:x2+y2-2y-4=0可化為x2+(y-1)2=5,其圓心坐標(biāo)(0,1),半徑r=√5,點(diǎn)(0,1)到直線l的距離為d=("|" 3×0+1"-" 6"|" )/√(3^2+1^2 )=√10/2,所以半弦長(zhǎng)為("|" AB"|" )/2=√(r^2 "-" d^2 )=√("(" √5 ")" ^2 "-" (√10/2) ^2 )=√10/2,所以弦長(zhǎng)|AB|=√10.
直線的兩點(diǎn)式方程教學(xué)設(shè)計(jì)人教A版高中數(shù)學(xué)選擇性必修第一冊(cè)
解析：①過(guò)原點(diǎn)時(shí)，直線方程為y＝－34x.②直線不過(guò)原點(diǎn)時(shí)，可設(shè)其方程為xa＋ya＝1，∴4a＋－3a＝1，∴a＝1.∴直線方程為x＋y－1＝0.所以這樣的直線有2條，選B.答案：B4.若點(diǎn)P(3,m)在過(guò)點(diǎn)A(2,-1),B(-3,4)的直線上,則m= . 解析:由兩點(diǎn)式方程得,過(guò)A,B兩點(diǎn)的直線方程為(y"-(-" 1")" )/(4"-(-" 1")" )=(x"-" 2)/("-" 3"-" 2),即x+y-1=0.又點(diǎn)P(3,m)在直線AB上,所以3+m-1=0,得m=-2.答案:-2 5.直線ax+by=1(ab≠0)與兩坐標(biāo)軸圍成的三角形的面積是 . 解析:直線在兩坐標(biāo)軸上的截距分別為1/a 與 1/b,所以直線與坐標(biāo)軸圍成的三角形面積為1/(2"|" ab"|" ).答案:1/(2"|" ab"|" )6.已知三角形的三個(gè)頂點(diǎn)A(0,4)，B(－2,6)，C(－8,0)．(1)求三角形三邊所在直線的方程；(2)求AC邊上的垂直平分線的方程．解析(1)直線AB的方程為y－46－4＝x－0－2－0，整理得x＋y－4＝0；直線BC的方程為y－06－0＝x＋8－2＋8，整理得x－y＋8＝0；由截距式可知，直線AC的方程為x－8＋y4＝1，整理得x－2y＋8＝0.(2)線段AC的中點(diǎn)為D(－4,2)，直線AC的斜率為12，則AC邊上的垂直平分線的斜率為－2，所以AC邊的垂直平分線的方程為y－2＝－2(x＋4)，整理得2x＋y＋6＝0.
點(diǎn)到直線的距離公式教學(xué)設(shè)計(jì)人教A版高中數(shù)學(xué)選擇性必修第一冊(cè)
4.已知△ABC三個(gè)頂點(diǎn)坐標(biāo)A(－1,3)，B(－3,0)，C(1,2)，求△ABC的面積S.【解析】由直線方程的兩點(diǎn)式得直線BC的方程為 ＝ ，即x－2y＋3＝0，由兩點(diǎn)間距離公式得|BC|＝ ，點(diǎn)A到BC的距離為d，即為BC邊上的高，d＝ ，所以S＝ |BC|·d＝ ×2 × ＝4，即△ABC的面積為4.5.已知直線l經(jīng)過(guò)點(diǎn)P(0,2),且A(1,1),B(-3,1)兩點(diǎn)到直線l的距離相等,求直線l的方程.解:(方法一)∵點(diǎn)A(1,1)與B(-3,1)到y(tǒng)軸的距離不相等,∴直線l的斜率存在,設(shè)為k.又直線l在y軸上的截距為2,則直線l的方程為y=kx+2,即kx-y+2=0.由點(diǎn)A(1,1)與B(-3,1)到直線l的距離相等,∴直線l的方程是y=2或x-y+2=0.得("|" k"-" 1+2"|" )/√(k^2+1)=("|-" 3k"-" 1+2"|" )/√(k^2+1),解得k=0或k=1.(方法二)當(dāng)直線l過(guò)線段AB的中點(diǎn)時(shí),A,B兩點(diǎn)到直線l的距離相等.∵AB的中點(diǎn)是(-1,1),又直線l過(guò)點(diǎn)P(0,2),∴直線l的方程是x-y+2=0.當(dāng)直線l∥AB時(shí),A,B兩點(diǎn)到直線l的距離相等.∵直線AB的斜率為0,∴直線l的斜率為0,∴直線l的方程為y=2.綜上所述,滿足條件的直線l的方程是x-y+2=0或y=2.
兩點(diǎn)間的距離公式教學(xué)設(shè)計(jì)人教A版高中數(shù)學(xué)選擇性必修第一冊(cè)
一、情境導(dǎo)學(xué)在一條筆直的公路同側(cè)有兩個(gè)大型小區(qū),現(xiàn)在計(jì)劃在公路上某處建一個(gè)公交站點(diǎn)C,以方便居住在兩個(gè)小區(qū)住戶的出行.如何選址能使站點(diǎn)到兩個(gè)小區(qū)的距離之和最小?二、探究新知問(wèn)題1.在數(shù)軸上已知兩點(diǎn)A、B，如何求A、B兩點(diǎn)間的距離？提示：|AB|＝|xA－xB|.問(wèn)題2：在平面直角坐標(biāo)系中能否利用數(shù)軸上兩點(diǎn)間的距離求出任意兩點(diǎn)間距離？探究.當(dāng)x1≠x2，y1≠y2時(shí)，|P1P2|＝？請(qǐng)簡(jiǎn)單說(shuō)明理由．提示：可以，構(gòu)造直角三角形利用勾股定理求解．答案：如圖，在Rt △P1QP2中，|P1P2|2＝|P1Q|2＋|QP2|2，所以|P1P2|＝?x2－x1?2＋?y2－y1?2.即兩點(diǎn)P1(x1，y1)，P2(x2，y2)間的距離|P1P2|＝?x2－x1?2＋?y2－y1?2.你還能用其它方法證明這個(gè)公式嗎？2．兩點(diǎn)間距離公式的理解(1)此公式與兩點(diǎn)的先后順序無(wú)關(guān)，也就是說(shuō)公式也可寫成|P1P2|＝?x2－x1?2＋?y2－y1?2.(2)當(dāng)直線P1P2平行于x軸時(shí)，|P1P2|＝|x2－x1|.當(dāng)直線P1P2平行于y軸時(shí)，|P1P2|＝|y2－y1|.
傾斜角與斜率教學(xué)設(shè)計(jì)人教A版高中數(shù)學(xué)選擇性必修第一冊(cè)
(2)l的傾斜角為90°,即l平行于y軸,所以m+1=2m,得m=1.延伸探究1 本例條件不變,試求直線l的傾斜角為銳角時(shí)實(shí)數(shù)m的取值范圍.解:由題意知(m"-" 1"-" 1)/(m+1"-" 2m)>0,解得1<m<2.延伸探究2 若將本例中的“N(2m,1)”改為“N(3m,2m)”,其他條件不變,結(jié)果如何?解:(1)由題意知(m"-" 1"-" 2m)/(m+1"-" 3m)=1,解得m=2.(2)由題意知m+1=3m,解得m=1/2.直線斜率的計(jì)算方法(1)判斷兩點(diǎn)的橫坐標(biāo)是否相等,若相等,則直線的斜率不存在.(2)若兩點(diǎn)的橫坐標(biāo)不相等,則可以用斜率公式k=(y_2 "-" y_1)/(x_2 "-" x_1 )(其中x1≠x2)進(jìn)行計(jì)算.金題典例 光線從點(diǎn)A(2,1)射到y(tǒng)軸上的點(diǎn)Q,經(jīng)y軸反射后過(guò)點(diǎn)B(4,3),試求點(diǎn)Q的坐標(biāo)及入射光線的斜率.解:(方法1)設(shè)Q(0,y),則由題意得kQA=-kQB.∵kQA=(1"-" y)/2,kQB=(3"-" y)/4,∴(1"-" y)/2=-(3"-" y)/4.解得y=5/3,即點(diǎn)Q的坐標(biāo)為 0,5/3 ,∴k入=kQA=(1"-" y)/2=-1/3.(方法2)設(shè)Q(0,y),如圖,點(diǎn)B(4,3)關(guān)于y軸的對(duì)稱點(diǎn)為B'(-4,3), kAB'=(1"-" 3)/(2+4)=-1/3,由題意得,A、Q、B'三點(diǎn)共線.從而入射光線的斜率為kAQ=kAB'=-1/3.所以,有(1"-" y)/2=(1"-" 3)/(2+4),解得y=5/3,點(diǎn)Q的坐標(biāo)為(0,5/3).
兩條平行線間的距離教學(xué)設(shè)計(jì)人教A版高中數(shù)學(xué)選擇性必修第一冊(cè)
一、情境導(dǎo)學(xué)前面我們已經(jīng)得到了兩點(diǎn)間的距離公式，點(diǎn)到直線的距離公式，關(guān)于平面上的距離問(wèn)題，兩條直線間的距離也是值得研究的。思考1：立定跳遠(yuǎn)測(cè)量的什么距離？A.兩平行線的距離 B.點(diǎn)到直線的距離 C. 點(diǎn)到點(diǎn)的距離二、探究新知思考2：已知兩條平行直線l_1,l_2的方程，如何求l_1 〖與l〗_2間的距離？根據(jù)兩條平行直線間距離的含義，在直線l_1上取任一點(diǎn)P（x_0,y_0 ），,點(diǎn)P（x_0,y_0 ）到直線l_2的距離就是直線l_1與直線l_2間的距離，這樣求兩條平行線間的距離就轉(zhuǎn)化為求點(diǎn)到直線的距離。兩條平行直線間的距離1. 定義：夾在兩平行線間的__________的長(zhǎng).公垂線段2. 圖示： 3. 求法：轉(zhuǎn)化為點(diǎn)到直線的距離.1．原點(diǎn)到直線x＋2y－5＝0的距離是( )A．2 B．3 C．2 D．5D [d＝|－5|12＋22＝5.選D.]
圓與圓的位置關(guān)系教學(xué)設(shè)計(jì)人教A版高中數(shù)學(xué)選擇性必修第一冊(cè)
1.兩圓x2+y2-1=0和x2+y2-4x+2y-4=0的位置關(guān)系是( )A.內(nèi)切 B.相交 C.外切 D.外離解析:圓x2+y2-1=0表示以O(shè)1(0,0)點(diǎn)為圓心,以R1=1為半徑的圓.圓x2+y2-4x+2y-4=0表示以O(shè)2(2,-1)點(diǎn)為圓心,以R2=3為半徑的圓.∵|O1O2|=√5,∴R2-R1<|O1O2|<R2+R1,∴圓x2+y2-1=0和圓x2+y2-4x+2y-4=0相交.答案:B2.圓C1:x2+y2-12x-2y-13=0和圓C2:x2+y2+12x+16y-25=0的公共弦所在的直線方程是 . 解析:兩圓的方程相減得公共弦所在的直線方程為4x+3y-2=0.答案:4x+3y-2=03.半徑為6的圓與x軸相切,且與圓x2+(y-3)2=1內(nèi)切,則此圓的方程為( )A.(x-4)2+(y-6)2=16 B.(x±4)2+(y-6)2=16C.(x-4)2+(y-6)2=36 D.(x±4)2+(y-6)2=36解析:設(shè)所求圓心坐標(biāo)為(a,b),則|b|=6.由題意,得a2+(b-3)2=(6-1)2=25.若b=6,則a=±4;若b=-6,則a無(wú)解.故所求圓方程為(x±4)2+(y-6)2=36.答案:D4.若圓C1:x2+y2=4與圓C2:x2+y2-2ax+a2-1=0內(nèi)切,則a等于 . 解析:圓C1的圓心C1(0,0),半徑r1=2.圓C2可化為(x-a)2+y2=1,即圓心C2(a,0),半徑r2=1,若兩圓內(nèi)切,需|C1C2|=√(a^2+0^2 )=2-1=1.解得a=±1. 答案:±1 5. 已知兩個(gè)圓C1:x2+y2=4,C2:x2+y2-2x-4y+4=0,直線l:x+2y=0,求經(jīng)過(guò)C1和C2的交點(diǎn)且和l相切的圓的方程.解:設(shè)所求圓的方程為x2+y2+4-2x-4y+λ(x2+y2-4)=0,即(1+λ)x2+(1+λ)y2-2x-4y+4(1-λ)=0.所以圓心為 1/(1+λ),2/(1+λ) ,半徑為1/2 √((("-" 2)/(1+λ)) ^2+(("-" 4)/(1+λ)) ^2 "-" 16((1"-" λ)/(1+λ))),即|1/(1+λ)+4/(1+λ)|/√5=1/2 √((4+16"-" 16"(" 1"-" λ^2 ")" )/("(" 1+λ")" ^2 )).解得λ=±1,舍去λ=-1,圓x2+y2=4顯然不符合題意,故所求圓的方程為x2+y2-x-2y=0.
直線的點(diǎn)斜式方程教學(xué)設(shè)計(jì)人教A版高中數(shù)學(xué)選擇性必修第一冊(cè)
【答案】B [由直線方程知直線斜率為3，令x＝0可得在y軸上的截距為y＝－3.故選B.]3．已知直線l1過(guò)點(diǎn)P(2,1)且與直線l2：y＝x＋1垂直，則l1的點(diǎn)斜式方程為_(kāi)_______．【答案】y－1＝－(x－2) [直線l2的斜率k2＝1，故l1的斜率為－1，所以l1的點(diǎn)斜式方程為y－1＝－(x－2)．]4．已知兩條直線y＝ax－2和y＝(2－a)x＋1互相平行，則a＝________. 【答案】1 [由題意得a＝2－a，解得a＝1.]5.無(wú)論k取何值,直線y-2=k(x+1)所過(guò)的定點(diǎn)是 . 【答案】(-1,2)6．直線l經(jīng)過(guò)點(diǎn)P(3,4)，它的傾斜角是直線y＝3x＋3的傾斜角的2倍，求直線l的點(diǎn)斜式方程．【答案】直線y＝3x＋3的斜率k＝3，則其傾斜角α＝60°，所以直線l的傾斜角為120°.以直線l的斜率為k′＝tan 120°＝－3.所以直線l的點(diǎn)斜式方程為y－4＝－3(x－3)．
人教版高中政治必修4綜合探究：堅(jiān)持唯物辯證法，反對(duì)形而上學(xué)教案
5．循環(huán)經(jīng)濟(jì)當(dāng)前，發(fā)展循環(huán)經(jīng)濟(jì)和知識(shí)經(jīng)濟(jì)已成為國(guó)際社會(huì)的兩大趨勢(shì)，有的發(fā)達(dá)國(guó)家甚至以立法的方式加以推進(jìn)。循環(huán)經(jīng)濟(jì)本質(zhì)上是一種生態(tài)經(jīng)濟(jì)，它要求運(yùn)用生態(tài)學(xué)規(guī)律而不是機(jī)械的規(guī)律來(lái)指導(dǎo)人類社會(huì)的經(jīng)濟(jì)活動(dòng)，減量化、再利用和資源化是其三大原則。傳統(tǒng)經(jīng)濟(jì)是一種“資源——產(chǎn)品——污染排放”單向流動(dòng)的線性經(jīng)濟(jì)，特征是高開(kāi)采、低利用、高排放；與之不同，循環(huán)經(jīng)濟(jì)倡導(dǎo)的是一種與環(huán)境和諧的經(jīng)濟(jì)發(fā)展模式，它要求把經(jīng)濟(jì)活動(dòng)組織成一個(gè)“資源——產(chǎn)品——再生資源”的反饋式流程，特征是低開(kāi)采、高利用、低排放。目前，我國(guó)已經(jīng)把發(fā)展循環(huán)經(jīng)濟(jì)作為編制“十一五”規(guī)劃的重要指導(dǎo)原則。6．當(dāng)心被優(yōu)勢(shì)“絆倒”有三個(gè)旅行者同時(shí)住進(jìn)一家旅店，早上同時(shí)出門旅游。晚上歸來(lái)時(shí)，拿傘的人淋得渾身是水，拿拐杖的人跌得滿身是傷，而什么也沒(méi)有帶的人卻安然無(wú)恙。
人教版新課標(biāo)小學(xué)數(shù)學(xué)六年級(jí)下冊(cè)郵票中的數(shù)學(xué)問(wèn)題教案
《貼郵票》活動(dòng)要求：A、每組4人，給四封不同地點(diǎn)、質(zhì)量的信件B、根據(jù)信封上的信息計(jì)算郵費(fèi)并按要求貼上郵票（郵票的總面值剛好等于郵費(fèi)，不能多貼）每封信最多貼三張郵票，只有0.8元或1.2元的兩種郵票紀(jì)律要求：看看哪組合作得最好，速度最快！如果遇到困難，在事發(fā)那個(gè)在一邊最后再去解決。3、小組匯報(bào)（1）、貼郵票的過(guò)程中大家遇到了什么問(wèn)題？（有的能貼有的不能貼）這樣的信件有哪些？（告訴我地點(diǎn)、質(zhì)量、郵費(fèi)）（2）、其他的信件都能貼出來(lái)嘛？說(shuō)說(shuō)看你是怎么貼郵票的？（3）、請(qǐng)將你們貼好郵票的信件送到郵箱來(lái)。剩下的都是一些“難題”（4）、思考：為什么4.0元、4.8元、6元的郵費(fèi)沒(méi)有辦法按要求貼出郵票？（5）、原因出在哪里？這個(gè)問(wèn)題怎么解決？（郵票面值太小，將郵票的面值改大）（6）、那最少要改成多大的？為什么？（將郵票面值改大，你會(huì)從多大面值的郵票開(kāi)始考慮？為什么？）
人教版高中歷史必修1甲午中日戰(zhàn)爭(zhēng)說(shuō)課稿
3．甲午中日戰(zhàn)爭(zhēng)中國(guó)戰(zhàn)敗的原因 對(duì)于“中國(guó)戰(zhàn)敗的原因”這一難點(diǎn)的突破，主要通過(guò)設(shè)置問(wèn)題“中國(guó)之?dāng)≡趯?shí)力遜于日本嗎？”通過(guò)幻燈片全方位分析其實(shí)中國(guó)的綜合國(guó)力當(dāng)時(shí)是強(qiáng)于日本的。并且在戰(zhàn)前，日本毫無(wú)取勝的把握。讓學(xué)生結(jié)合剛學(xué)習(xí)過(guò)的戰(zhàn)爭(zhēng)原因和經(jīng)過(guò)進(jìn)行討論，從多方面分析中國(guó)戰(zhàn)敗的原因。經(jīng)過(guò)討論，學(xué)生可以得出以下結(jié)論：避戰(zhàn)自保方針，沒(méi)有積極備戰(zhàn)，將領(lǐng)臨陣脫逃，教師肯定并總結(jié)答案進(jìn)行補(bǔ)充。中日對(duì)比：中國(guó)士兵出身農(nóng)民，軍事訓(xùn)練落后，散兵游勇；日本士兵出身武士，訓(xùn)練有素；中國(guó)將領(lǐng)大多臨陣脫逃，并相互猜忌，受當(dāng)時(shí)惡劣的官風(fēng)影響；李鴻章深知北洋海軍實(shí)情，缺乏軍費(fèi)，軍備廢弛。為政治資本奉行避戰(zhàn)自保政策，慈禧太后挪用海軍軍費(fèi)過(guò)壽，支持李鴻章。使中方處于被動(dòng)的局面，一再貽誤戰(zhàn)機(jī)。而日本在天皇的帶動(dòng)下，全民備戰(zhàn)，做了充分的戰(zhàn)爭(zhēng)準(zhǔn)備。
人教版高中生物必修1細(xì)胞中的無(wú)機(jī)物說(shuō)課稿
為了加強(qiáng)學(xué)生的理解，讓學(xué)生討論以下問(wèn)題。由師生共同總結(jié)。播放一個(gè)短時(shí)視頻，讓學(xué)生認(rèn)識(shí)到水的重要性后，展示節(jié)水標(biāo)識(shí)，說(shuō)明由來(lái)。細(xì)胞中的無(wú)機(jī)鹽這部分，我將展示圖表，并列出問(wèn)題：表中哪些成分屬于無(wú)機(jī)鹽？為什么要在運(yùn)動(dòng)員喝的飲料中添加無(wú)機(jī)鹽？無(wú)機(jī)鹽在細(xì)胞的生活中起什么作用？然后展示廣告語(yǔ)，讓學(xué)生思考和討論以下問(wèn)題，并得到答案。再閱讀課本，驗(yàn)證自己的答案是否正確。關(guān)于無(wú)機(jī)鹽的作用較難理解，通過(guò)列舉人體生活與健康中的各種實(shí)例來(lái)加深感性認(rèn)識(shí)，加強(qiáng)對(duì)理論知識(shí)的理解3、課堂小結(jié)，強(qiáng)化認(rèn)識(shí)。（3—5分鐘）課堂小結(jié)，可以把課堂傳授的知識(shí)盡快地轉(zhuǎn)化為學(xué)生的素質(zhì)；簡(jiǎn)單扼要的課堂小結(jié)，可使學(xué)生更深刻地理解理論知識(shí)在實(shí)際生活中的應(yīng)用，并且逐漸地培養(yǎng)學(xué)生具有良好的個(gè)性。4、板書(shū)設(shè)計(jì)我比較注重直觀、系統(tǒng)的板書(shū)設(shè)計(jì)，還及時(shí)地體現(xiàn)教材中的知識(shí)點(diǎn)，以便于學(xué)生能夠理解掌握。5、布置作業(yè)。
高中生物蘇教版必修一《31生命活動(dòng)及本單位-細(xì)胞》教案
本章是第三章第一節(jié)的開(kāi)端，學(xué)生在第二節(jié)已經(jīng)學(xué)習(xí)了元素的組成和一些生物大分子，本節(jié)課內(nèi)容是學(xué)會(huì)使用顯微鏡，這是生物學(xué)習(xí)過(guò)程中最為重要的一種手段之一。對(duì)于今后的實(shí)驗(yàn)學(xué)習(xí)有著極其重要的作用。 學(xué)生中大部分同學(xué)在初中階段都有接觸過(guò)光學(xué)顯微鏡，所以在學(xué)習(xí)理論知識(shí)的時(shí)候能夠順利的進(jìn)行，但因?yàn)閷W(xué)校的條件有限，不能保證同學(xué)們進(jìn)行顯微鏡的實(shí)驗(yàn)，本節(jié)課結(jié)合學(xué)生情況和實(shí)際情況，采用圖片和模型展示的方法進(jìn)行。 知識(shí)與能力 1、概述細(xì)胞學(xué)說(shuō)建立的過(guò)程。 2、概述細(xì)胞學(xué)說(shuō)的內(nèi)容和意義。 3、學(xué)習(xí)制作臨時(shí)玻片標(biāo)本，使用顯微鏡和繪圖的能。
新人教版高中英語(yǔ)必修3Unit 3 Diverse Cultures教學(xué)設(shè)計(jì)四
該板塊的活動(dòng)主題是“介紹一個(gè)有顯著文化特征的地方”( Describe a place with distinctive cultural identity)。該板塊通過(guò)介紹中國(guó)城繼續(xù)聚焦中國(guó)文化。本單元主題圖呈現(xiàn)的是舊金山中國(guó)城的典型景象, Reading and Thinking部分也提到中國(guó)城,為該板塊作鋪墊。介紹中國(guó)城的目的主要是體現(xiàn)中國(guó)文化與美國(guó)多元文化的關(guān)系,它是美國(guó)多元文化的重要組成部分。中國(guó)城也是海外華人的精神家園和傳播中國(guó)文化的重要窗口,外國(guó)人在中國(guó)城能近距離體驗(yàn)中國(guó)文化。1. Read the text to understand the cultural characteristics of Chinatown in San Francisco and the relationship between Chinese culture and American multiculturalism;2. Through reading, learn to comb the main information of the article, understand the author's writing purpose and writing characteristics;3. Learn to give a comprehensive, accurate, and organized description of the city or town you live in;Learn to revise and evaluate your writing.Importance:1. Guide the students to read the introduction of Chinatown in San Francisco and grasp its writing characteristics;2. Guide students to introduce their city or town in a comprehensive, accurate and organized way;3. Learn to comb the main information of the article, understand the author's writing purpose, and master the core vocabulary.
新人教版高中英語(yǔ)必修3Unit 1 Festivals and Celebrations教學(xué)設(shè)計(jì)二
1. Ss look at the picture and scan the passage to understand the main idea while teacher is giving the following questions to inspire Ss to think.*Where are those people?*What are they doing?*Why are they so excited?2. Ss complete the passage with the appropriate -ing form. Then discuss and check the answers with class.Answers: boring, interesting, taking, exciting, amazing3. The teacher raises questions for the students to discuss and encourages them to express their opinions.*Do you like La Tomatina? Why or why not?4. Each group representative reports the discussion result, the teacher gives feedback and the evaluation.Step 6 PracticeActivity 41. Ss complete the Ex 2 in Using structures.2. Check the answers after finishing the exercises.①The dragon boat races are the most exciting part of the Dragon Boat Festival.② The children were excited to go Easter egg hunting.③What an amazing performance! This is the best music festival I have ever been to.④We were amazed by her funny-looking hat.⑤His inspiring speech at the conference won the admiration/ favour of the audience.⑥This is a challenging game to test your memory and observation capabilities. 3. T asks Ss to finish Ex 3 and 4 in Using structures by themselves, then check the answers with class.Step 6 Homework1. Understand and master the functions and usage of the -ing form;2. Finish the other exercises in Using structures.1、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生是否理解和掌握動(dòng)詞-ing形式作定語(yǔ)和表語(yǔ)的功能和意義；2、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生能否在理解文段內(nèi)容的基礎(chǔ)上，根據(jù)上下文語(yǔ)境和表達(dá)邏輯，能正確運(yùn)用動(dòng)詞-ing形式描述節(jié)日慶典。3、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生是否歸納和積累用于表達(dá)情緒的相關(guān)詞匯。
新人教版高中英語(yǔ)必修3Unit 3 Diverse Cultures教學(xué)設(shè)計(jì)二
(2)Consolidate key vocabulary.Ask the students to complete the exercises of activity 6 by themselves. Then ask them to check the answers with their partners.(The first language:Damage of the 1906 San Francisco earthquake and fire.A second language: Yunnan - one of the most diverse provinces in China).Step 5 Language points1. The teacher asks the students to read the text carefully, find out the more words and long and difficult sentences in the text and draw lines, understand the use of vocabulary, and analyze the structure of long and difficult sentences.2. The teacher explains and summarizes the usage of core vocabulary and asks the students to take notes.3. The teacher analyzes and explains the long and difficult sentences that the students don't understand, so that the students can understand them better.Step 6 Homework1. Read the text again, in-depth understanding of the text;2. Master the use of core vocabulary and understand the long and difficult sentences.3. Complete relevant exercises in the guide plan.1、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生是否理解和掌握閱讀文本中的新詞匯的意義與用法；2、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生能否結(jié)合文本特點(diǎn)了解文章的結(jié)構(gòu)和作者的寫作邏輯；3、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生能否了解舊金山的城市風(fēng)貌、文化特色，以及加利福尼亞州的歷史，體會(huì)多元文化對(duì)美國(guó)的影響。
高中語(yǔ)文人教版必修三《動(dòng)物游戲之謎》說(shuō)課稿
科學(xué)是人類認(rèn)識(shí)世界的重要工具，閱讀科普說(shuō)明文不僅可以啟迪心智，了解更多知識(shí)。而且更夠激發(fā)學(xué)生對(duì)科學(xué)的興趣。學(xué)習(xí)這些文章要注重學(xué)生科學(xué)精神的培養(yǎng)，關(guān)注科學(xué)探索的過(guò)程，感受科學(xué)家在科學(xué)探索中表現(xiàn)的人格魅力。我們知道一些科學(xué)家就是因?yàn)殚喿x了相關(guān)的科普文章才對(duì)某一學(xué)科產(chǎn)生興趣，從而走上成功之路的。我們?cè)谥v解的時(shí)候可以跟學(xué)生列舉一些例子，讓學(xué)生認(rèn)識(shí)到一篇好的科普文章的重大意義。
高中歷史人教版必修一《馬克思主義的誕生》說(shuō)課稿
一、教學(xué)理念在新課改精神指導(dǎo)下，我在本課教學(xué)中力求貫徹以下教學(xué)理念：新課標(biāo)的指引觀 、生本位的學(xué)生觀、探究式的學(xué)習(xí)觀、多角色的教師觀、 發(fā)展性的評(píng)價(jià)觀二、教材地位《馬克思主義的誕生》是人教版必修一第五單元第18課內(nèi)容，本課講述的是國(guó)際共產(chǎn)主義運(yùn)動(dòng)范疇的歷史，是人類社會(huì)進(jìn)入一個(gè)新的發(fā)展時(shí)期。從總體上概述了社會(huì)主義從空想到科學(xué)，從理論到實(shí)踐的歷程。說(shuō)明了科學(xué)社會(huì)主義理論是歷史發(fā)展的必然結(jié)果。本課在國(guó)際工運(yùn)史上占有重要的地位。通過(guò)學(xué)習(xí)學(xué)生可對(duì)馬克思主義加深了解，理解人類歷史發(fā)展的必然趨勢(shì)以及人類一直不斷追求進(jìn)步的精神，幫助學(xué)生樹(shù)立正確的人生觀、價(jià)值觀，達(dá)到以史鑒今，服務(wù)現(xiàn)實(shí)的目的。
人教版高中英語(yǔ)必修4A taste of English Humor說(shuō)課稿3篇
Then I would ask them to think of a funny English or Chinese and tell it to partners. While telling stories, they can use expressions and some acting to help make the story funny. 5 minutes would be given to do this.Those stories they told there will be the material for their writing. Soletting them tell it at first is helpful. And they can make a difference between telling a funny story and writing it down. Generally speaking, it is difficult forstudents to write well because they don’t know what to write and how to write. Asking them to tell their own stories at first can help them come up with what to write.After their telling, I would invite someone to share his/her story with all of us and I would write it down on the blackboard.This example story would be used as a sample to illustrate the format of funny story. Different from a story from teacher or textbook, a story from students can obviously become a interesting material to draw students’ attention.Then I would ask the whole class to put this story into several parts. It might be a little bit difficult for them. So I would ask them to find out whether all the sentences are necessary. After delete some sentences, there are 6 sentences left behind. Then they can easily put them into three parts. After interaction with students, I would teach them the right terms for each part and conclude the format of funny story.This step is the key and difficult point in my lesson. So I mainly usetask-based teaching method in this part and the task for students was divided into several stages. With the separated difficult level, students can find there are usually three parts in writing. They can also learn to write without the unnecessary parts in the process of analyzing. And then I wouldn’t rush to tell them the right terms to them directly. Instead, I would ask them to name them by their own. A confused mind is better for acquiring knowledge.While-writing:Then I would give students 7 minutes to write down this story, without other requirements.With all the preparations in pre-writing, students’ difficulties were cleared. So it would be much easier for them to write down the story within 7 minutes. There are no other requirements because students’ first writing is actually a drafting. It would be revise and edit several times later. Writing, as a skill
人教版高中英語(yǔ)必修5First aid說(shuō)課稿6篇
In this class, I have 3 teaching aims, that is, knowledge aims, ability aims and emotion aims.1) Knowledge-Teach students new words and expressions, such as temporary, bleed,sprain choke, first aid, fall ill and so on.-Enable students to have a better understanding for some basic knowledge of first aid.2) Ability-Train students’ speaking, reading and writing abilities by different teaching activities, such as skimming, comprehending, team work, role play, retelling and writing.-Develop students’ reading strategy on how to move general idea to specific information.3) Emotion-Promote students’ awareness of giving first aid.- Cultivate students’ creativities.Then let’s come to my teaching methods and activities.III. Teaching methods and activities:To achieve different teaching aims, various kinds of teaching methods and activities will be adopted throughout this period, such as TBL (task-based learning), skimming, team work, brainstorm and others, which can offer students opportunities to fulfill tasks in which they can use language to achieve a specific outcome.IV. Teaching aids:Computer and blackboardV. Teaching important points:1) Make students have a clear mind for the structure of the text.2) Help students understand the theme of the text.VI. Teaching difficulties:1) So many new words may affect students’ understanding.2) How to get students to know about the functions of the skin and thecauses, characteristics and treatments for different degree burns,and the knowledge about giving first aid. VII. Blackboard design:
