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新人教版高中英語必修3Unit 4 Space ExplorationReading and Thinking教學(xué)設(shè)計一

  • 新人教版高中英語必修1Unit 3 Sports and Fitness-Reading and Thinking教案

    新人教版高中英語必修1Unit 3 Sports and Fitness-Reading and Thinking教案

    2. Sort out detailed information about Michael Jordan.(1) Understand the transitional sentence.Q: Which part is about Michael Jordan as a master? Which part is about the example he set?(2) Have the Ss Focus on why Michael Jordan is a master and what good examples Michael Jordan set when they’re reading. And think about these questions as below:Q1: How does the author describe his impressive skills?Q2: How do you understand “time seemed to stand still”?Q3: What does “graceful” mean?Q4. Which sentence do you think best describes his mental strength?Q5. Which words is important in the sentence in describing his mental strength? Why?Q6: How do you understand “unique”?Q7: What can we learn from Michael Jordan?Step 5 Discussing and recommendingRecommend their own living legends of sports.Work in groups to choose your own living legend of sports and give the reasons of your choice. Step 6 HomeworkReview the stories of Lang Ping and Michael Jordan, and try to retell them.

  • 新人教版高中英語必修2Unit 3 The Internet-Reading and Thinking教案二

    新人教版高中英語必修2Unit 3 The Internet-Reading and Thinking教案二

    Q5:What's Jan's next goal?Her next goal is to start a charity website to raise money for children in poor countries.Q6:What can we learn from her experiences?We learn that when we go through tough times, we can find help and support from other people online. We learn that we can feel less lonelyStep 5: While reading---rethinkingQ1: What is Jan’s attitude to the Internet ?Thankful/Grateful, because it has changed her and her life.Q2: What writing skills is used in the article ?Examples(Jan’s example, the 59-year-old man’s and the 61-year-old woman’s example)Q3: Can you get the main idea of the article ?The Internet has changed Jan’s life/Jan’s life has been changed by the Internet.Step 6 Post reading---Retell the storyMuch has been written about the wonders of the World Wide Web. There are countless articles (1)telling(tell) us how the Internet has made our lives more convenient. But the Internet has done a lot (2)more(much) for people than simply make life more convenient. People’s lives (3) have been changed(change) by online communities and social networks so far. Take Jan for example, who developed a serious illness that made her (4)stuck(stick) at home with only her computer to keep (5)her(she) company. She joined an online group (6)where she could share problems, support and advice with others. She considered the ability to remove the distance between people as one of the greatest (7)benefits(benefit). She was so inspired (8)that she started an IT club in which many people have been helped. She has started to learn more about how to use the Internet to make society better. Her next goal is to start a charity website to raise money (9)for children in poor countries. Jan’s life has been (10)greatly(great) improved by the Internet.

  • 人教A版高中數(shù)學(xué)必修一二次函數(shù)與一元二次方程、不等式教學(xué)設(shè)計(2)

    人教A版高中數(shù)學(xué)必修一二次函數(shù)與一元二次方程、不等式教學(xué)設(shè)計(2)

    三個“二次”即一元二次函數(shù)、一元二次方程、一元二次不等式是高中數(shù)學(xué)的重要內(nèi)容,具有豐富的內(nèi)涵和密切的聯(lián)系,同時也是研究包含二次曲線在內(nèi)的許多內(nèi)容的工具 高考試題中近一半的試題與這三個“二次”問題有關(guān) 本節(jié)主要是幫助考生理解三者之間的區(qū)別及聯(lián)系,掌握函數(shù)、方程及不等式的思想和方法。課程目標(biāo)1. 通過探索,使學(xué)生理解二次函數(shù)與一元二次方程,一元二次不等式之間的聯(lián)系。2. 使學(xué)生能夠運用二次函數(shù)及其圖像,性質(zhì)解決實際問題. 3. 滲透數(shù)形結(jié)合思想,進(jìn)一步培養(yǎng)學(xué)生綜合解題能力。數(shù)學(xué)學(xué)科素養(yǎng)1.數(shù)學(xué)抽象:一元二次函數(shù)與一元二次方程,一元二次不等式之間的聯(lián)系;2.邏輯推理:一元二次不等式恒成立問題;3.數(shù)學(xué)運算:解一元二次不等式;4.數(shù)據(jù)分析:一元二次不等式解決實際問題;5.數(shù)學(xué)建模:運用數(shù)形結(jié)合的思想,逐步滲透一元二次函數(shù)與一元二次方程,一元二次不等式之間的聯(lián)系。

  • 人教A版高中數(shù)學(xué)必修一兩角和與差的正弦、余弦和正切公式教學(xué)設(shè)計(2)

    人教A版高中數(shù)學(xué)必修一兩角和與差的正弦、余弦和正切公式教學(xué)設(shè)計(2)

    本節(jié)內(nèi)容是三角恒等變形的基礎(chǔ),是正弦線、余弦線和誘導(dǎo)公式等知識的延伸,同時,它又是兩角和、差、倍、半角等公式的“源頭”。兩角和與差的正弦、余弦、正切是本章的重要內(nèi)容,對于三角變換、三角恒等式的證明和三角函數(shù)式的化簡、求值等三角問題的解決有著重要的支撐作用。 課程目標(biāo)1、能夠推導(dǎo)出兩角和與差的正弦、余弦、正切公式并能應(yīng)用; 2、掌握二倍角公式及變形公式,能靈活運用二倍角公式解決有關(guān)的化簡、求值、證明問題.?dāng)?shù)學(xué)學(xué)科素養(yǎng)1.數(shù)學(xué)抽象:兩角和與差的正弦、余弦和正切公式; 2.邏輯推理: 運用公式解決基本三角函數(shù)式的化簡、證明等問題;3.數(shù)學(xué)運算:運用公式解決基本三角函數(shù)式求值問題.4.數(shù)學(xué)建模:學(xué)生體會到一般與特殊,換元等數(shù)學(xué)思想在三角恒等變換中的作用。.

  • 人教A版高中數(shù)學(xué)必修一兩角和與差的正弦、余弦和正切公式教學(xué)設(shè)計(1)

    人教A版高中數(shù)學(xué)必修一兩角和與差的正弦、余弦和正切公式教學(xué)設(shè)計(1)

    本節(jié)課選自《普通高中課程標(biāo)準(zhǔn)實驗教科書數(shù)學(xué)必修1本(A版)》第五章的5.5.1 兩角和與差的正弦、余弦和正切公式。本節(jié)的主要內(nèi)容是由兩角差的余弦公式的推導(dǎo),運用誘導(dǎo)公式、同角三角函數(shù)的基本關(guān)系和代數(shù)變形,得到其它的和差角公式。讓學(xué)生感受數(shù)形結(jié)合及轉(zhuǎn)化的思想方法。發(fā)展學(xué)生數(shù)學(xué)直觀、數(shù)學(xué)抽象、邏輯推理、數(shù)學(xué)建模的核心素養(yǎng)。課程目標(biāo) 學(xué)科素養(yǎng)1.了解兩角差的余弦公式的推導(dǎo)過程.2.掌握由兩角差的余弦公式推導(dǎo)出兩角和的余弦公式及兩角和與差的正弦、正切公式.3.熟悉兩角和與差的正弦、余弦、正切公式的靈活運用,了解公式的正用、逆用以及角的變換的常用方法.4.通過正切函數(shù)圖像與性質(zhì)的探究,培養(yǎng)學(xué)生數(shù)形結(jié)合和類比的思想方法。 a.數(shù)學(xué)抽象:公式的推導(dǎo);b.邏輯推理:公式之間的聯(lián)系;c.數(shù)學(xué)運算:運用和差角角公式求值;d.直觀想象:兩角差的余弦公式的推導(dǎo);e.數(shù)學(xué)建模:公式的靈活運用;

  • 高中數(shù)學(xué)人教版必修二直線的點斜式方程教案

    高中數(shù)學(xué)人教版必修二直線的點斜式方程教案

    【教學(xué)重點】直線的點斜式方程、斜截式方程的確定.【教學(xué)難點】直線的點斜式方程、斜截式方程的確定.【教學(xué)過程】1、對特殊三角函數(shù)進(jìn)行鞏固復(fù)習(xí);表1 內(nèi)特殊三角函數(shù)值 不存在圖1 特殊三角形2、鞏固復(fù)習(xí)直線的傾斜角和斜率相關(guān)內(nèi)容;直線的傾斜角:,;直線的斜率: , ;設(shè)點為直線l上的任意兩點,當(dāng)時,

  • 高中數(shù)學(xué)人教版必修二直線的點斜式方程教案

    高中數(shù)學(xué)人教版必修二直線的點斜式方程教案

    【教學(xué)目標(biāo)】知識目標(biāo):理解直線的點斜式方程、斜截式方程、橫截距、縱截距的概念;掌握直線的點斜式方程、斜截式方程的確定.能力目標(biāo):通過求解直線的點斜式方程和斜截式方程,培養(yǎng)學(xué)生的數(shù)學(xué)思維能力與數(shù)形結(jié)合的數(shù)學(xué)思想.情感目標(biāo):通過學(xué)習(xí)直線的點斜式方程和斜截式方程,體會數(shù)形結(jié)合的直觀感受.【教學(xué)重點】直線的點斜式方程、斜截式方程的確定.【教學(xué)難點】直線的點斜式方程、斜截式方程的確定.

  • 人教版高中數(shù)學(xué)選修3超幾何分布教學(xué)設(shè)計

    人教版高中數(shù)學(xué)選修3超幾何分布教學(xué)設(shè)計

    探究新知問題1:已知100件產(chǎn)品中有8件次品,現(xiàn)從中采用有放回方式隨機抽取4件.設(shè)抽取的4件產(chǎn)品中次品數(shù)為X,求隨機變量X的分布列.(1):采用有放回抽樣,隨機變量X服從二項分布嗎?采用有放回抽樣,則每次抽到次品的概率為0.08,且各次抽樣的結(jié)果相互獨立,此時X服從二項分布,即X~B(4,0.08).(2):如果采用不放回抽樣,抽取的4件產(chǎn)品中次品數(shù)X服從二項分布嗎?若不服從,那么X的分布列是什么?不服從,根據(jù)古典概型求X的分布列.解:從100件產(chǎn)品中任取4件有 C_100^4 種不同的取法,從100件產(chǎn)品中任取4件,次品數(shù)X可能取0,1,2,3,4.恰有k件次品的取法有C_8^k C_92^(4-k)種.一般地,假設(shè)一批產(chǎn)品共有N件,其中有M件次品.從N件產(chǎn)品中隨機抽取n件(不放回),用X表示抽取的n件產(chǎn)品中的次品數(shù),則X的分布列為P(X=k)=CkM Cn-kN-M CnN ,k=m,m+1,m+2,…,r.其中n,N,M∈N*,M≤N,n≤N,m=max{0,n-N+M},r=min{n,M},則稱隨機變量X服從超幾何分布.

  • 人教版高中數(shù)學(xué)選修3二項式定理教學(xué)設(shè)計

    人教版高中數(shù)學(xué)選修3二項式定理教學(xué)設(shè)計

    二項式定理形式上的特點(1)二項展開式有n+1項,而不是n項.(2)二項式系數(shù)都是C_n^k(k=0,1,2,…,n),它與二項展開式中某一項的系數(shù)不一定相等.(3)二項展開式中的二項式系數(shù)的和等于2n,即C_n^0+C_n^1+C_n^2+…+C_n^n=2n.(4)在排列方式上,按照字母a的降冪排列,從第一項起,次數(shù)由n次逐項減少1次直到0次,同時字母b按升冪排列,次數(shù)由0次逐項增加1次直到n次.1.判斷(正確的打“√”,錯誤的打“×”)(1)(a+b)n展開式中共有n項. ( )(2)在公式中,交換a,b的順序?qū)Ω黜棝]有影響. ( )(3)Cknan-kbk是(a+b)n展開式中的第k項. ( )(4)(a-b)n與(a+b)n的二項式展開式的二項式系數(shù)相同. ( )[解析] (1)× 因為(a+b)n展開式中共有n+1項.(2)× 因為二項式的第k+1項Cknan-kbk和(b+a)n的展開式的第k+1項Cknbn-kak是不同的,其中的a,b是不能隨便交換的.(3)× 因為Cknan-kbk是(a+b)n展開式中的第k+1項.(4)√ 因為(a-b)n與(a+b)n的二項式展開式的二項式系數(shù)都是Crn.[答案] (1)× (2)× (3)× (4)√

  • 人教版高中數(shù)學(xué)選修3條件概率教學(xué)設(shè)計

    人教版高中數(shù)學(xué)選修3條件概率教學(xué)設(shè)計

    (2)方法一:第一次取到一件不合格品,還剩下99件產(chǎn)品,其中有4件不合格品,95件合格品,于是第二次又取到不合格品的概率為4/99,由于這是一個條件概率,所以P(B|A)=4/99.方法二:根據(jù)條件概率的定義,先求出事件A,B同時發(fā)生的概率P(AB)=(C_5^2)/(C_100^2 )=1/495,所以P(B|A)=(P"(" AB")" )/(P"(" A")" )=(1/495)/(5/100)=4/99.6.在某次考試中,要從20道題中隨機地抽出6道題,若考生至少答對其中的4道題即可通過;若至少答對其中5道題就獲得優(yōu)秀.已知某考生能答對其中10道題,并且知道他在這次考試中已經(jīng)通過,求他獲得優(yōu)秀成績的概率.解:設(shè)事件A為“該考生6道題全答對”,事件B為“該考生答對了其中5道題而另一道答錯”,事件C為“該考生答對了其中4道題而另2道題答錯”,事件D為“該考生在這次考試中通過”,事件E為“該考生在這次考試中獲得優(yōu)秀”,則A,B,C兩兩互斥,且D=A∪B∪C,E=A∪B,由古典概型的概率公式及加法公式可知P(D)=P(A∪B∪C)=P(A)+P(B)+P(C)=(C_10^6)/(C_20^6 )+(C_10^5 C_10^1)/(C_20^6 )+(C_10^4 C_10^2)/(C_20^6 )=(12" " 180)/(C_20^6 ),P(E|D)=P(A∪B|D)=P(A|D)+P(B|D)=(P"(" A")" )/(P"(" D")" )+(P"(" B")" )/(P"(" D")" )=(210/(C_20^6 ))/((12" " 180)/(C_20^6 ))+((2" " 520)/(C_20^6 ))/((12" " 180)/(C_20^6 ))=13/58,即所求概率為13/58.

  • 人教版高中數(shù)學(xué)選修3正態(tài)分布教學(xué)設(shè)計

    人教版高中數(shù)學(xué)選修3正態(tài)分布教學(xué)設(shè)計

    3.某縣農(nóng)民月均收入服從N(500,202)的正態(tài)分布,則此縣農(nóng)民月均收入在500元到520元間人數(shù)的百分比約為 . 解析:因為月收入服從正態(tài)分布N(500,202),所以μ=500,σ=20,μ-σ=480,μ+σ=520.所以月均收入在[480,520]范圍內(nèi)的概率為0.683.由圖像的對稱性可知,此縣農(nóng)民月均收入在500到520元間人數(shù)的百分比約為34.15%.答案:34.15%4.某種零件的尺寸ξ(單位:cm)服從正態(tài)分布N(3,12),則不屬于區(qū)間[1,5]這個尺寸范圍的零件數(shù)約占總數(shù)的 . 解析:零件尺寸屬于區(qū)間[μ-2σ,μ+2σ],即零件尺寸在[1,5]內(nèi)取值的概率約為95.4%,故零件尺寸不屬于區(qū)間[1,5]內(nèi)的概率為1-95.4%=4.6%.答案:4.6%5. 設(shè)在一次數(shù)學(xué)考試中,某班學(xué)生的分?jǐn)?shù)X~N(110,202),且知試卷滿分150分,這個班的學(xué)生共54人,求這個班在這次數(shù)學(xué)考試中及格(即90分及90分以上)的人數(shù)和130分以上的人數(shù).解:μ=110,σ=20,P(X≥90)=P(X-110≥-20)=P(X-μ≥-σ),∵P(X-μσ)≈2P(X-μ130)=P(X-110>20)=P(X-μ>σ),∴P(X-μσ)≈0.683+2P(X-μ>σ)=1,∴P(X-μ>σ)=0.158 5,即P(X>130)=0.158 5.∴54×0.158 5≈9(人),即130分以上的人數(shù)約為9人.

  • 人教版高中數(shù)學(xué)選修3組合與組合數(shù)教學(xué)設(shè)計

    人教版高中數(shù)學(xué)選修3組合與組合數(shù)教學(xué)設(shè)計

    解析:因為減法和除法運算中交換兩個數(shù)的位置對計算結(jié)果有影響,所以屬于組合的有2個.答案:B2.若A_n^2=3C_(n"-" 1)^2,則n的值為( )A.4 B.5 C.6 D.7 解析:因為A_n^2=3C_(n"-" 1)^2,所以n(n-1)=(3"(" n"-" 1")(" n"-" 2")" )/2,解得n=6.故選C.答案:C 3.若集合A={a1,a2,a3,a4,a5},則集合A的子集中含有4個元素的子集共有 個. 解析:滿足要求的子集中含有4個元素,由集合中元素的無序性,知其子集個數(shù)為C_5^4=5.答案:54.平面內(nèi)有12個點,其中有4個點共線,此外再無任何3點共線,以這些點為頂點,可得多少個不同的三角形?解:(方法一)我們把從共線的4個點中取點的多少作為分類的標(biāo)準(zhǔn):第1類,共線的4個點中有2個點作為三角形的頂點,共有C_4^2·C_8^1=48(個)不同的三角形;第2類,共線的4個點中有1個點作為三角形的頂點,共有C_4^1·C_8^2=112(個)不同的三角形;第3類,共線的4個點中沒有點作為三角形的頂點,共有C_8^3=56(個)不同的三角形.由分類加法計數(shù)原理,不同的三角形共有48+112+56=216(個).(方法二 間接法)C_12^3-C_4^3=220-4=216(個).

  • 人教版高中數(shù)學(xué)選修3排列與排列數(shù)教學(xué)設(shè)計

    人教版高中數(shù)學(xué)選修3排列與排列數(shù)教學(xué)設(shè)計

    4.有8種不同的菜種,任選4種種在不同土質(zhì)的4塊地里,有 種不同的種法. 解析:將4塊不同土質(zhì)的地看作4個不同的位置,從8種不同的菜種中任選4種種在4塊不同土質(zhì)的地里,則本題即為從8個不同元素中任選4個元素的排列問題,所以不同的種法共有A_8^4 =8×7×6×5=1 680(種).答案:1 6805.用1、2、3、4、5、6、7這7個數(shù)字組成沒有重復(fù)數(shù)字的四位數(shù).(1)這些四位數(shù)中偶數(shù)有多少個?能被5整除的有多少個?(2)這些四位數(shù)中大于6 500的有多少個?解:(1)偶數(shù)的個位數(shù)只能是2、4、6,有A_3^1種排法,其他位上有A_6^3種排法,由分步乘法計數(shù)原理,知共有四位偶數(shù)A_3^1·A_6^3=360(個);能被5整除的數(shù)個位必須是5,故有A_6^3=120(個).(2)最高位上是7時大于6 500,有A_6^3種,最高位上是6時,百位上只能是7或5,故有2×A_5^2種.由分類加法計數(shù)原理知,這些四位數(shù)中大于6 500的共有A_6^3+2×A_5^2=160(個).

  • 人教版高中數(shù)學(xué)選修3全概率公式教學(xué)設(shè)計

    人教版高中數(shù)學(xué)選修3全概率公式教學(xué)設(shè)計

    2.某小組有20名射手,其中1,2,3,4級射手分別為2,6,9,3名.又若選1,2,3,4級射手參加比賽,則在比賽中射中目標(biāo)的概率分別為0.85,0.64,0.45,0.32,今隨機選一人參加比賽,則該小組比賽中射中目標(biāo)的概率為________. 【解析】設(shè)B表示“該小組比賽中射中目標(biāo)”,Ai(i=1,2,3,4)表示“選i級射手參加比賽”,則P(B)= P(Ai)P(B|Ai)= 2/20×0.85+ 6/20 ×0.64+ 9/20×0.45+ 3/20×0.32=0.527 5.答案:0.527 53.兩批相同的產(chǎn)品各有12件和10件,每批產(chǎn)品中各有1件廢品,現(xiàn)在先從第1批產(chǎn)品中任取1件放入第2批中,然后從第2批中任取1件,則取到廢品的概率為________. 【解析】設(shè)A表示“取到廢品”,B表示“從第1批中取到廢品”,有P(B)= 112,P(A|B)= 2/11 ,P(A| )= 1/11所以P(A)=P(B)P(A|B)+P( )P(A| )4.有一批同一型號的產(chǎn)品,已知其中由一廠生產(chǎn)的占 30%, 二廠生產(chǎn)的占 50% , 三廠生產(chǎn)的占 20%, 又知這三個廠的產(chǎn)品次品率分別為2% , 1%, 1%,問從這批產(chǎn)品中任取一件是次品的概率是多少?

  • 新人教版高中英語必修1Unit 1 Teenage Life-Reading and Thinking教案

    新人教版高中英語必修1Unit 1 Teenage Life-Reading and Thinking教案

    【教材分析】The topic of this unit is about teenage life, which belongs to the theme context of “humans and oneself”.As teenagers who shoulder the responsibility of “Chinese great dream”, they must fully know themselves, including their strengths, weaknesses and challenges etc. They are supposed to improve themselves continuously and readily study their subjects, and thus foster their strategies and confidence in lifelong studies.This period is entitled the freshmen challenges, which mainly concerns some big challenges for new students in Senior high school. In this period, a teacher should lead students to find out what their challenges are and guide them to figure out how to crack the challenges and better themselves. More importantly, a teacher should instruct students to absorb new language points and appreciate the language. Besides, a teacher must instruct students to acquire some skills concerning reading efficiently and inspire them to talk more about their new school life, especially their new problems and solutions both at school and in life.【教學(xué)目標(biāo)與核心素養(yǎng)】1. Enable students to acquire the basic usage of the new words and expressions concerning the freshmen challenges and learn to use them flexibly.2. Enable students to have a good understanding of the freshmen challenges in the new senior high school which is quite different from junior middle school.3. Develop students’ sense of cooperative learning and individual thinking capability. 4. Develop students’ different learning skills to solve different reading comprehensive problems.

  • 新人教版高中英語必修1Unit 5 Languages Around the World-Reading and Thinking教案

    新人教版高中英語必修1Unit 5 Languages Around the World-Reading and Thinking教案

    【教材分析】本節(jié)課是高中英語第一冊的最后一個單元的閱讀和思考部分,文章難度明顯增加,體現(xiàn)在以下幾個方面:文章題材是說明文,比較難理解;話題生疏,涉及到歷史等知識;生詞量增大,而且在語境中理解詞匯的要求提高。面對這些,教師的難度和高度也要有所提升,通過探討說明順序,了解背景知識等幫助他們找到說明文閱讀的方法?!窘虒W(xué)目標(biāo)與核心素養(yǎng)】1. 文化意識目標(biāo)新課程中指出,文化意識是對中外文化的理解和對優(yōu)秀文化的認(rèn)同。文化意識的的培養(yǎng)有助于學(xué)生增加國家認(rèn)同和家國情懷,成為有文明素養(yǎng)和社會責(zé)任感的人。我們這個單元很好體現(xiàn)了這一點,通過了解漢字書寫的體系和發(fā)展,學(xué)生可以有一種文化自豪感,同時也能夠幫助學(xué)生深入挖掘這篇文章,從而想到更多和中國文化相關(guān)的方面。2. 學(xué)習(xí)能力目標(biāo)

  • 新人教版高中英語必修1Welcome Unit-Reading and Thinking教案

    新人教版高中英語必修1Welcome Unit-Reading and Thinking教案

    Step 2 New WordsUse ppt to show some words from the passage.Tell the students to remember the meanings.Step3 Skimming and Thinking1. Skim the text and decide which order Han Jing follows to talk about her first day. Time order or place order?Time order2. What is Han Jing worried about before she goes to senior high school?She is worried about whether she will make new friends and if no one talks to her, what she should do.Step 4 Fast Reading1. Match the main ideas with each paragraphParagraph 1:The worries about the new school day Paragraph 2Han Jing’s first maths classParagraph 3Han Jing’s first chemistry classParagraph 4Han Jing’s feelings about her first senior school dayStep 5 Careful Reading1. Fill in the chart with the words and phrases about Han Jing’s day. Answers: Senior high school, a little nervous; Her first maths class, classmates and teachers, friendly and helpful; Chemistry lab; new; great; annoying guy; Confident; a lot to explore2. Read the text again and discuss the questions.1) Why did Han Jing feel anxious before school?Because she was a new senior high student and she was not outgoing. What was more, she was worried about whether she can make friends.2) How was her first maths class?It was difficult but the teacher was kind and friendly. 3) What happened in the chemistry class? What would you do if this happened to you? A guy next to Han Jing tried to talk with her and she couldn’t concentrate on the experiment.

  • 新人教版高中英語必修2Unit 1 Cultural Heritage-Reading and Thinking教案二

    新人教版高中英語必修2Unit 1 Cultural Heritage-Reading and Thinking教案二

    1. This section focuses on "Understanding how a problem was solved”, which is aimed to guide students to analyze and discuss the challenges and problems faced by cultural heritage protection during the construction of Aswan Dam, as well as the solutions. On the basis of understanding, students should pay attention to the key role of international cooperation in solving problems, and attach importance to the balance and coordination between cultural heritage protection and social and economic development. Students are encouraged to face challenges actively, be good at cooperation, and make continuous efforts to find reasonable ways and means to solve problems.2. Enable students to understand the main information and text structure of the reading text;3. Motivate students to use the reading strategy "make a timeline" according to the appropriate text genre;4. Enable students to understand how a problem was solved;5. Enable students to understand the value of protecting cultural heritage by teamwork and global community;1. Guide students to pay attention to reading strategies, such as prediction, self-questioning and scanning.2. Help students sort out the topic language about protecting cultural relics and understand the narrative characteristics of "time-event" in illustrative style3. Lead students to understand the value of protecting cultural heritage by teamwork and global community;

  • 新人教版高中英語必修2Unit 2 Wildlife Protection-Reading and Thinking教案二

    新人教版高中英語必修2Unit 2 Wildlife Protection-Reading and Thinking教案二

    The theme of this unit is human and nature, focusing on the theme of wildlife protection. Nature is a complex ecosystem, in which there are delicate balance between animals and plants. Because of the role of the food chain, the extinction of one species will produce influence, causing a series of chain reaction. Large scale extinction of species will have a serious and even irreversible impact on the ecosystem, resulting in immeasurable losses. Therefore, it is of great significance to protect wild species. To protect wild species is to protect human beings themselves. The motto of this unit is "when the buying stops, the killing can too,” which is a public service advertising slogan to protect wildlife. It tells people that every rhinoceros horn, every fur, every bowl of shark fin soup, every Ivory product, and every tiger bone product, etc. consumed by human beings, are innocent wild animals slaughtered behind them. The mission of wild aid is to ban illegal trade in endangered wildlife and mitigate climate change. It aims to educate the public to reduce the consumption demand for endangered wildlife products through public publicity and improve the awareness of environmental protection.1. Improve the awareness of wildlife protection by acquiring the knowledge of wildlife protection.2. Focus on environmental protection and protection of all lives.3. Analysis of the living environment of wild animals with appropriate thinking mode.4. Skillfully use the vocabulary and grammar knowledge of this unit to cultivate self-study ability according to the unit content5. Develop cooperative learning ability through discussion and other ways1. Enable the Ss to talk about the current situation of wild animals.2. Guide the Ss to summarize the main idea of each paragraph as well as the main idea of the text.

  • 新人教版高中英語必修2Unit 5 Music-Reading and Thinking教案二

    新人教版高中英語必修2Unit 5 Music-Reading and Thinking教案二

    1. Get basic information about Eric; read deeply to understand the history and development of the virtual choir.2. Understand what the function of the virtual choir is and how to make a virtual choir.3. Understand the meaning of some languages in the context of the text through question guidance, such as “Many people do not have close friends or contacts who have the same interest in music.” and so on.Step 1 Leading-in1. Answer the following questions.Q1:Do you know the Apps like Tik Tok and Quick Hand?Q2: Do you want to make a Tik Tok video or a Quick Hand video?2. Play a Tik Tok video Step 2: Understanding the title Q1:What does the title mean ?Q2: Is the article a narration or exposition? Why? Q3: Can you change the title ? If you can, what is the title?Step 3: Scanning the whole text and getting the basic information1. Answer the following questions.Q1:Who came up with the idea for a virtual choir?Q2: Where did Eric studied the musical composition?Q3: What is his song?2. Find the main idea of each paragraph3. Deal with some new words.Step 4: Reading carefully to get detailed informationPara 1 How to make a virtual choir1. PreparationA. tools: a virtual camera; an Internet connectionB. hero/heroin: friends or some individuals who have the same interests2. Process

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